Advertisements
Advertisements
Question
A recent survey found that the ages of workers in a factory is distributed as follows:
Age (in years) | 20 – 29 | 30 – 39 | 40 – 49 | 50 – 59 | 60 and above |
Number of workers | 38 | 27 | 86 | 46 | 3 |
If a person is selected at random, find the probability that the person is:
- 40 years or more
- under 40 years
- having age from 30 to 39 years
- under 60 but over 39 years
Solution
Total number of workers in a factory,
n(S) = 38 + 27 + 86 + 46 + 3 = 200
i. Number of persons selected at the age of 40 years or more,
n(E1) = 86 + 46 + 3 = 135
∴ Probability that the persons selected at the age of 40 years or more,
`P(E_1) = (n(E_1))/(n(S))`
= `135/200`
= 0.675
Hence, the probability that the person selected at the age of 40 years or more is 0.675.
ii. Number of persons selected under the age of 40 years
n(E2) = 38 + 27 = 65
∴ Probability that the persons selected under the age of 40 years,
`P(E_2) = (n(E_2))/(n(S))`
= `65/200`
= 0.325
Hence, the probability that the persons selected under the age of 40 years is 0.325.
iii. Number of persons selected having age from 30 to 39 years,
n(E3) = 27
∴ Probability that the person selected having age from 30 to 39 years,
`P(E_3) = (n(E_3))/(n(S))`
= `27/200`
= 0.135
Hence, the probability that the person selected having age from 30 to 39 years is 0.135.
iv. Number of persons selected having age under 60 but over 39 years,
n(E4) = 86 + 46 = 132
∴ Probability that the person selected having age under 60 but over 39 years,
`P(E_4) = (n(E_4))/(n(S))`
= `132/200`
= 0.66
Hence, the probability that the person selected having age under 60 but over 39 years is 0.66.
APPEARS IN
RELATED QUESTIONS
Three coins are tossed simultaneously 200 times with the following frequencies of different outcomes:-
Outcome | 3 heads | 2 heads | 1 head | No head |
Frequency | 23 | 72 | 77 | 28 |
If the three coins are simultaneously tossed again, compute the probability of 2 heads coming up.
Eleven bags of wheat flour, each marked 5 Kg, actually contained the following weights of flour (in kg):
4.97, 5.05, 5.08, 5.03, 5.00, 5.06, 5.08, 4.98, 5.04, 5.07, 5.00
Find the probability that any of these bags chosen at random contains more than 5 kg of flour.
Given below is the frequency distribution of wages (in Rs) of 30 workers in a certain factory:
Wages (in Rs) | 110-130 | 130-150 | 150-170 | 170-190 | 190-210 | 210-230 | 230-250 |
No. of workers | 3 | 4 | 5 | 6 | 5 | 4 | 3 |
A worker is selected at random. Find the probability that his wages are:
(i) less than Rs 150
(ii) at least Rs 210
(iii) more than or equal to 150 but less than Rs 210.
The probability an event of a trial is
Two coins are tossed simultaneously. The probability of getting atmost one head is
A dice is rolled 600 times and the occurrence of the outcomes 1, 2, 3, 4, 5 and 6 are given below:
Outcome | 1 | 2 | 3 | 4 | 5 | 6 |
Frequency | 200 | 30 | 120 | 100 | 50 | 100 |
The probability of getting a prime number is
Two dice are thrown simultaneously 500 times. Each time the sum of two numbers appearing on their tops is noted and recorded as given in the following table:
Sum | Frequency |
2 | 14 |
3 | 30 |
4 | 42 |
5 | 55 |
6 | 72 |
7 | 75 |
8 | 70 |
9 | 53 |
10 | 46 |
11 | 28 |
12 | 15 |
If the dice are thrown once more, what is the probability of getting a sum more than 10?
Bulbs are packed in cartons each containing 40 bulbs. Seven hundred cartons were examined for defective bulbs and the results are given in the following table:
Number of defective bulbs | 0 | 1 | 2 | 3 | 4 | 5 | 6 | more than 6 |
Frequency | 400 | 180 | 48 | 41 | 18 | 8 | 3 | 2 |
One carton was selected at random. What is the probability that it has defective bulbs less than 4?
Over the past 200 working days, the number of defective parts produced by a machine is given in the following table:
Number of defective parts |
0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 | 11 | 12 | 13 |
Days | 50 | 32 | 22 | 18 | 12 | 12 | 10 | 10 | 10 | 8 | 6 | 6 | 2 | 2 |
Determine the probability that tomorrow’s output will have
- no defective part
- atleast one defective part
- not more than 5 defective parts
- more than 13 defective parts
Over the past 200 working days, the number of defective parts produced by a machine is given in the following table:
Number of defective parts |
0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 | 11 | 12 | 13 |
Days | 50 | 32 | 22 | 18 | 12 | 12 | 10 | 10 | 10 | 8 | 6 | 6 | 2 | 2 |
Determine the probability that tomorrow’s output will have atleast one defective part