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Karnataka Board PUCPUC Science Class 11

Air is Pumped into an Automobile Tyre'S Tube up to a Pressure of 200 Kpa in the Morning When the Air Temperature is 20°C. During the Day the Temperature Rises to 40°C and the Tube Expands by 2%. - Physics

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Question

Air is pumped into an automobile tyre's tube up to a pressure of 200 kPa in the morning when the air temperature is 20°C. During the day the temperature rises to 40°C and the tube expands by 2%. Calculate the pressure of the air in the tube at this temperature.

Sum

Solution

Here,

\[ P_1 = 2 \times {10}^5 Pa \]

P2 = ?

T1 = 293  K

T2 = 313  K

V2 = V1 + 0.02 V1 = V1 (1.02)

Now,

\[ \frac{P_1 V_1}{T_1} = \frac{P_2 V_2}{T_2} \]

\[\Rightarrow \frac{2 \times {10}^5 V_1}{293} = \frac{P_2 V_1 (1.02)}{313} \]

\[ \Rightarrow P_2 = \frac{2 \times {10}^5 \times 313}{293 \times 1.02} = 209 \text{ kPa }\]

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Kinetic Theory of Gases - Concept of Pressure
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Chapter 2: Kinetic Theory of Gases - Exercises [Page 35]

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HC Verma Concepts of Physics Vol. 2 [English] Class 11 and 12
Chapter 2 Kinetic Theory of Gases
Exercises | Q 23 | Page 35

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