Advertisements
Advertisements
Question
Alcohols are comparatively more soluble in water than hydrocarbons of comparable molecular masses. Explain this fact.
Solution
Alcohols are more soluble in water compared to hydrocarbons with equivalent molecular weight because alcohol molecules form hydrogen bonds with water and can also break the existing hydrogen bonds between water molecules, while hydrocarbons are unable to do this.
APPEARS IN
RELATED QUESTIONS
Give reasons for the following : Phenol is more acidic than ethanol.
Give reason for the higher boiling point of ethanol in comparison to methoxymethane.
`CH_3-CH_2-Br"Alcoholic KOH"/""> B " HBR"/"">C"Na/Eather"/"">D`, the Compound D is
(A) ethane
(B) propane
(C) n-butane
(D) n-pentane
Give simple chemical tests to distinguish between the following pairs of compounds :
Ethanol and phenol
Arrange the following compounds in the increasing order of their acid strength:
p-cresol, p-nitrophenol, phenol
Identify the chiral molecule in the following pair :
Which statement is not correct about alcohol?
Which one of the following alcohols is least soluble in water?
Explain why alcohols and ethers of comparable molecular mass have different boiling points?
Assertion: Boiling points of alcohols and ethers are high.
Reason: They can form intermolecular hydrogen-bonding.
A solution of phenol in chloroform when treated with aqueous NaOH gives compound P as a major product. The mass percentage of carbon in P is ______. (to the nearest integer) (Atomic mass: C = 12; H = 1; O = 16)
Assertion (A): Alcohols react both as nucleophiles and electrophiles.
Reason (R): The bond between C–O is broken when alcohols react as nucleophiles.
Select the most appropriate answer from the options given below:
Write a note on Kolbe's reaction
What is esterifications? How is an ester obtained from alcohol or phenol?
Convert the following:
acetaldehyde to isopropyl alcohol.
How are the following conversions carried out?
\[\ce{Methyl magnesium bromide -> 2-Methylpropan-2-ol}\]
How is the following conversion carried out?
\[\ce{Methyl magnesium bromide-> 2-Methylpropan-2-ol}\]
How is the following conversions carried out?
\[\ce{Methyl magnesium bromide → 2-Methylpropan-2-ol}\].