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Tamil Nadu Board of Secondary EducationHSC Science Class 11

At particular temperature Kc = 4 × 10-2 for the reaction, HX2S(g)↽−−⇀HX2(g)+12SX2(g). Calculate the Kc for the following reaction. 2HX2S(g)↽−−⇀2HX2(g)+SX2(g) - Chemistry

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Question

At particular temperature Kc = 4 × 10-2 for the reaction, \[\ce{H2S (g) <=> H2(g) +1/2 S2(g)}\]. Calculate the Kc for the following reaction.

\[\ce{2H2S (g) <=> 2H2 (g) + S2 (g)}\]

Numerical

Solution

KC = 4 x 10-2 for the reaction

\[\ce{H2S (g) <=> H2(g) +1/2 S2(g)}\]

`"K"_"C" = (["H"_2]["S"_2]^(1/2))/(["H"_2"S"]) = 4 xx 10^-2`

For the reaction,

\[\ce{2H2S (g) <=> 2H2 (g) + S2 (g)}\]

`"K"_"C" = (["H"_2]^2["S"_2]^(1/2))/(["H"_2"S"]^2) = (4 xx 10^-2)^2`

= 16 × 10-4

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Equilibrium Constants
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Chapter 8: Physical and Chemical Equilibrium - Evaluation [Page 27]

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Samacheer Kalvi Chemistry - Volume 1 and 2 [English] Class 11 TN Board
Chapter 8 Physical and Chemical Equilibrium
Evaluation | Q II. 19. i) | Page 27

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