Advertisements
Advertisements
Question
By using identity evaluate the following:
`1 + 1/8 - 27/8`
Solution
We know that a3 + b3 + c3 = 0 then a + b + c = 3abc
`1 + 1/8 - 27/8 = 1^3 + (1/2)^3 - (3/2)^3`
a + b + c = `1 + 1/2 - 3/2`
= `(2 + 1 - 3)/2`
= `0/2`
= 0
`1 + 1/8 - 27/8 = 3(1) xx 1/2 xx ((-3)/2)`
= `(-9)/4`
APPEARS IN
RELATED QUESTIONS
Show that `(4/3 m - 3/4 n)^2 + 2mn = 16/9 m^2 + 9/16 n^2`
Find the following product: (x + 4) (x + 7)
Expand the following:
(3a + 1)(3a – 2)(3a + 4)
Using algebraic identity, find the coefficients of x2, x and constant term without actual expansion
(x + 5)(x + 6)(x + 7)
Evaluate the following by using identities:
983
Simplify:
(2.5m + 1.5q)2 + (2.5m – 1.5q)2
Simplify:
(x2 – 4) + (x2 + 4) + 16
Simplify:
(b2 – 49)(b + 7) + 343
Expand the following, using suitable identities.
`(4/5p + 5/3q)^2`
Carry out the following division:
–121p3q3r3 ÷ (–11xy2z3)
