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Question
Choose the correct alternative:
Fisher’s Price Index Number is
Options
`sqrt("P"_(01)("L") xx "P"_(01)("P"))`
P01(L) × P01(P)
`sqrt("P"_(01)("L") xx "P"_(01)("P")) xx 100`
`sqrt("P"_(01)("L") + "P"_(01)("P"))`
Solution
`sqrt("P"_(01)("L") xx "P"_(01)("P"))`
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