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Question
Complete the following diagrams shown in the below figure by drawing the reflected ray for each incident ray.
Solution
A light ray when produced backwards passes through principal focus as shown in the problem figure. We draw the normal through the centre of curvature at the point of incidence and draw the reflected ray at an angle equal to the angle of incidence thus following the laws of reflection. The reflected ray is parallel to the principal axis. The other ray is passing through the centre of curvature as shown in the problem figure. This ray retraces its incident path because it strikes the mirror normally i.e. 90 degrees. These two reflected rays when produced backwards coincide at a point where the image is formed. The image, A'B' is virtual, erect, and diminished in size.
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