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Question
Consider a simple pendulum of length l = 0.9 m which is properly placed on a trolley rolling down on a inclined plane which is at θ = 45° with the horizontal. Assuming that the inclined plane is frictionless, calculate the time period of oscillation of the simple pendulum.
Solution
Length of the pendulum l = 0.9 m
Inclined angle θ = 45°
Time period of a simple pendulum T = `2π sqrt("l"/"g’")`
g’ = g cos θ
T = `2π sqrt("l"/("g" cos θ))`
= `2 xx 3.14 xx sqrt(0.9/(9.8 xx cos 45°))`
= `6.28 xx sqrt(0.1298)`
T = 2.263 s
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