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Question
Consider the following frequency distribution:
| Class | 0 – 6 | 6 – 12 | 12 – 18 | 18 – 24 | 24 – 30 |
| Frequency | 12 | 10 | 15 | 8 | 11 |
The median class is:
Options
6 – 12
12 – 18
18 – 24
24 – 30
Solution
12 – 18
Explanation:
We have,
`\implies` N = 56
`\implies` N/2 = 28
Cumulative frequency just greater than or equal to 28 lies in interval 12 – 18
So, Median class is 12 – 18
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