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Question
Define self-inductance.
Solution
The self-inductance of a circuit is the ratio of magnetic flux (produced due to current in the circuit) linked with the circuit to the current flowing in it.
RELATED QUESTIONS
Explain the phenomenon of self induction
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An inductor may store energy in
What is the unit of self-inductance of a coil?
A coil of wire of a certain radius has 600 turns and a self-inductance is 108 mH. The self-inductance of a second similar coil of 500 turns will be:
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Consider an infinitely long wire carrying a current I(t), with `(dI)/(dt) = λ` = constant. Find the current produced in the rectangular loop of wire ABCD if its resistance is R (Figure).
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Calculate the self-inductance of a coil using the following data obtained when an AC source of frequency `(200/pi)` Hz and a DC source are applied across the coil.
AC Source | ||
S.No. | V (volts) | I (A) |
1 | 3.0 | 0.5 |
2 | 6.0 | 1.0 |
3 | 9.0 | 1.5 |
DC Source | ||
S.No. | V (volts) | I (A) |
1 | 4.0 | 1.0 |
2 | 6.0 | 1.5 |
3 | 8.0 | 2.0 |
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- self-inductance of coil.
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State the factors on which the magnetic coupling coefficient of two coils depends.
Obtain an expression for the self inductance of a solenoid.
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What is meant by magnetic coupling coefficient?