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Doubly-ionised Helium Ions Are Projected with a Speed of 10 Km S−1 in a Direction Perpendicular to a Uniform Magnetic Field of Magnitude 1.0 T. Find (A) the Force - Physics

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Question

Doubly-ionised helium ions are projected with a speed of 10 km s−1 in a direction perpendicular to a uniform magnetic field of magnitude 1.0 T. Find (a) the force acting on an ion (b) the radius of the circle in which it circulates and (c) the time taken by an ion to complete the circle.

Sum

Solution

Given:
Speed of the helium ions, v = 10 km s−1 = 104 m/s
Uniform magnetic field, B = 1.0 T
Charge on the helium ions = 2e
Mass of the helium ions, m = 4 × 1.6 × 10-27 kg
(a) The force acting on an ion,
qvBsinθ
= 2 × 1.6 × 10−19 × 104 × 1.0
= 3.2 × 10−15 N
(b) The radius of the circle in which it circulates,
`r = (mv)/(qB)`
= `(4xx1.6xx10^27xx10^4)/(2xx1.6xx10^-9xx1)`

=`(2xx10^-23)/(10^-19)`
(c) The time taken by an ion to complete the circle,
`T = (2pir)/(v)`
= `(6.28xx2.1xx10^-4)/(10^4)`

= 1.31 × 10−7 s

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Force on a Moving Charge in Uniform Magnetic and Electric Fields
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Chapter 12: Magnetic Field - Exercises [Page 233]

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HC Verma Concepts of Physics Vol. 2 [English] Class 11 and 12
Chapter 12 Magnetic Field
Exercises | Q 35 | Page 233

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