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Question
Draw a ∆ABC in which AB = 4 cm, BC = 5 cm and AC = 6 cm. Then construct another triangle whose sides are\[\frac{3}{5}\] of the corresponding sides of ∆ABC ?
Solution
Steps of Construction
Step 1
Draw a line segment AB = 4 cm. Taking point A as the centre and radius 6 cm, draw an arc. Similarly, taking point B as the centre and radius 5 cm, draw another arc. The arcs will intersect at point C. Now, join AC and BC to obtain the required triangle ABC.
Step 2
Draw a ray AX making an acute angle with line AB on the opposite side of vertex C.
Step 3
Locate five points A1, A2, A3, A4 and A5 on line AX such that AA1 = A1A2 = A2A3 = A3A4 = A4A5
Step 4
Join BA5 and draw a line through A3 parallel to BA5 to intersect AB at point B'.
Step 5
Draw a line through B' parallel to line BC to intersect AC at C'.
AB'C' is the required triangle.
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