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Question
Draw the graphs of the following equations on the same system of co-ordinates. Write the co-ordinates of their points of intersection.
x + 4 = 0, y - 1 = 0, 2x + 3 = 0, 3y - 15 = 0
Solution
∴ x + 4 = 0
⇒ x = −4
x = −4 is the equation of the line parallel to Y-axis at a distance of 4 units from it to its left.
∴ y − 1 = 0
⇒ y = 1
y = 1 is the equation of the line parallel to X-axis at a distance of 1 unit and above the X-axis.
∴ 2x + 3 = 0
⇒ x = `-3/2`
`x = - 3/2` is the equation of the line parallel to Y-axis at a distance of `3/2` units from it to its left.
∴ 3y − 15 = 0
⇒ y = `15/3`
⇒ y = 5
y = 5 is the equation of the line parallel to X-axis at a distance of 5 units and above the X-axis.
It can be seen from the figure that the co-ordinates of the points of intersection are `(-3/2 , 1), (-3/2 , 5),(-4,5) "and" (-4,1)`.
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