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Question
Expand.
(k + 4)3
Sum
Solution
It is known that,
`(a+b)^3 = a^3 + 3a^2b +3ab^2 + b^3`
= (k + 4)3 = `(k)^3 + 3 xx (k)^2 xx (4) + 3 xx (k) xx (4)^2 + (4)^3`
= `(k)^3 + 12(k)^2 + 3(k)(16) + 64`
= `k^3 + 12k^2 + 48k + 64`
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