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Question
Express the following as a single logarithm:
`(1)/(2)"log"25 - 2"log"3 + "log"36`
Solution
`(1)/(2)"log"25 - 2"log"3 + "log"36`
= `(1)/(2)"log"5^2 - 2"log"3 + "log"(2^2 xx 3^2)`
= `(1)/(2) xx 2"log"5 - 2"log"3 + "log"2^2 + "log3^2`
= log5 + 2log2
= log5 + log22
= log5 + log4
= log(5 x 4)
= log20.
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