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Maharashtra State BoardSSC (English Medium) 8th Standard

Factorise: 27m3 − 216n3 - Marathi (Second Language) [मराठी (द्वितीय भाषा)]

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Question

Factorise:

27m− 216n3

Sum

Solution 1

27m− 216n3

= 27 (m3 − 8n3)

= 27 (m3 − 2n3)

= 27 (m − 2n) (m2 + m × 2n + 2n2)

= 27 (m − 2n) (m2 + 2mn + 4n2)

27m− 216n3 = 27 (m − 2n) (m2 + 2mn + 4n2)

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Solution 2

27m− 216n3

= 33m3 − 63n3

= (3m)3 − (6n)3

= (3m − 6n) [(3m2) + (6n)2 + 3m.6n]

= (3m − 6n) (9m2 + 36n2 + 18mn)

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Chapter 6: Factorisation of Algebraic expressions - Practice Set 6.3 [Page 32]

APPEARS IN

Balbharati Mathematics [English] 8 Standard Maharashtra State Board
Chapter 6 Factorisation of Algebraic expressions
Practice Set 6.3 | Q 1.3 | Page 32
Balbharati Integrated 8 Standard Part 2 [English Medium] Maharashtra State Board
Chapter 3.1 Factorisation of Algebraic expressions
Practice Set 6.3 | Q 1. (3) | Page 47
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