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Maharashtra State BoardSSC (English Medium) 8th Standard

Simplify: 4x2−11x+616x2−9 - Marathi (Second Language) [मराठी (द्वितीय भाषा)]

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Question

Simplify:

\[\frac{4 x^2 - 11x + 6}{16 x^2 - 9}\]

Simplify

Solution

It is known that,

a2 − b= (a + b) (a − b)

\[\ \frac{4 x^2 - 11x + 6}{16 x^2 - 9}\]

\[ = \frac{4 x^2 - 8x - 3x + 6}{\left(4x \right)^2 - \left(3 \right)^2}\]

\[ = \frac{4x\left(x - 2 \right) - 3\left(x - 2 \right)}{\left(4x + 3 \right)\left(4x - 3 \right)}\]

\[ = \frac{\left(4x - 3 \right)\left(x - 2 \right)}{\left(4x + 3 \right)\left( 4x - 3 \right)}\]

\[ = \frac{x - 2}{4x + 3}\]

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Chapter 6: Factorisation of Algebraic expressions - Practice Set 6.4 [Page 33]

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Balbharati Mathematics [English] 8 Standard Maharashtra State Board
Chapter 6 Factorisation of Algebraic expressions
Practice Set 6.4 | Q 6 | Page 33
Balbharati Integrated 8 Standard Part 2 [English Medium] Maharashtra State Board
Chapter 3.1 Factorisation of Algebraic expressions
Practice Set 6.4 | Q 1. (6) | Page 48
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