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Maharashtra State BoardSSC (English Medium) 8th Standard

Simplify: p3 − (p + 1)3 - Marathi (Second Language) [मराठी (द्वितीय भाषा)]

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Question

Simplify:

p− (p + 1)3

Simplify

Solution 1

It is known that,

a3 − b3 = (a − b)(a2 + ab + b2)

p− (p + 1)3

= {p − (p + 1)} {(p)2 + (p + 1)2 + (p) × (p + 1)}

= (−1) (p2 + p2 + 1 + 2p + p2 + p)

= (−1)(3p2 + 3p + 1)

= −3p2 − 3p − 1

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Solution 2

p− (p + 1)3

We know that,

(a + b)3 = a3 + 3a2b + 3ab2 + b3

= p3 − (p3 + 3p2 + 3p + 1)

= p3 − p3 − 3p2 − 3p − 1

= −3p2 − 3p − 1

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Chapter 6: Factorisation of Algebraic expressions - Practice Set 6.3 [Page 32]

APPEARS IN

Balbharati Mathematics [English] 8 Standard Maharashtra State Board
Chapter 6 Factorisation of Algebraic expressions
Practice Set 6.3 | Q 2.4 | Page 32
Balbharati Integrated 8 Standard Part 2 [English Medium] Maharashtra State Board
Chapter 3.1 Factorisation of Algebraic expressions
Practice Set 6.3 | Q 2. (4) | Page 47
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