Advertisements
Advertisements
Question
Find the area of a ring whose outer and inner radii are respectively 23 cm and 12 cm.
Solution
Let r1 cm and r2 cm be the radii of the outer and inner boundaries of the ring, respectively.
We have:
r1 = 23 cm
r2 = 12 cm
Now,
Area of the outer ring `= π"r"_1^2`
`=22/7xx23xx23`
= 1662.57 cm2
Area of the inner ring `= π"r"_2^2`
`= 22/7xx12xx122`
= 452.57 cm2
Area of the ring = Area of the outer ring - Area of the inner ring
= 1662.57 - 452.57
= 1210 cm2
APPEARS IN
RELATED QUESTIONS
Prove that the area of a circular path of uniform width h surrounding a circular region of radius r is `pih(2r+h)`
A circle is inscribed in an equilateral triangle ABC is side 12 cm, touching its sides (the following figure). Find the radius of the inscribed circle and the area of the shaded part.
Write the formula for the area of a segment in a circle of radius r given that the sector angle is \[\theta\] (in degrees).
If the adjoining figure is a sector of a circle of radius 10.5 cm, what is the perimeter of the sector? (Take \[\pi = 22/7\])
What is the diameter of a circle whose area is equal to the sum of the areas of two circles of diameters 10 cm and 24 cm?
A square is inscribed in a circle of radius 7 cm. Find the area of the square.
The sum of the radii of two circles is 10.5 cm and the difference of their circumferences is 13.2 cm. Find the radii of the two circles.
Area of circle of radius ‘n’ units is
A pendulum swings through an angle of 30∘ and describes an arc 8.8 cm in length. Find the length of the pendulum in cm.
What is the diameter of a circle whose area is equal to the sum of the areas of two circles of radii 40cm and 9cm?