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Question
Find k, if A = `[(3, -2),(4, -2)]` and A2 = kA – 2I.
Solution
A2 = kA – 2I
∴ A.A + 2I = kA
∴ `[(3, -2),(4, -2)][(3, -2),(4, -2)] + 2[(1, 0),(0, 1)] = "k"[(3, -2),(4, -2)]`
∴ `[(9 - 8 ,-6 + 4),(12 - 8, -8 + 4)] + [(2, 0),(0, 2)] = [(3"k", -2"k"),(4"k", -2"k")]`
∴ `[(1, -2),(4, -4)] + [(2, 0),(0, 2)] = [(3"k", -2"k"),(4"k", -2"k")]`
∴ `[(1 + 2, -2 + 0),(4 + 0, -4 + 2)] = [(3"k", -2"k"),(4"k", -2"k")]`
∴ `[(3, -2),(4, -2)] = [(3"k", -2"k"),(4"k", -2"k")]`
∴ By equality of matrices, we get
3k = 3
∴ k = 1.
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