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Question
Find the length of the median through the vertex A of triangle ABC whose vertices are A (7, -3), B(S, 3) and C(3, -1).
Solution
We know that the median of triangle bisects the opposite side
∴ BD : DC = 1 : 1
Coordinates of D are ,
D (x , y) = D `((5 + 3)/2 , (3 - 1)/2) = "D" (4 , 1)`
Length of median AD = `sqrt ((7 - 4)^2 + (-3-1)^2) = sqrt (9 + 16) = sqrt 25` = 5 units
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