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Question
Find the maximum value of `|(1,1,1),(1,1+sintheta,1),(1,1,1+costheta)|`
Solution
`"Let "Delta = |(1,1,1),(1,1+sintheta,1),(1,1,1+costheta)|`
Applying R2 → R2 - R1 and R3 → R3 - R1, we get
`Delta=|(1,1,1),(0,sintheta,0),(0,0,costheta)|`
`Delta=sinthetacostheta`
`Delta=(sin2theta)/2`
We know that -1 ≤ sin2θ ≤ 1
∴ Maximum value of `Delta =1/2 xx 1 = 1/2`
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