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Find the Probability Distribution of the Number of Heads, When Three Coins Are Tossed. - Mathematics

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Question

Find the probability distribution of the number of heads, when three coins are tossed. 

Sum

Solution

Let X denote the number of heads in three tosses of a coin. Then, X can take the values 0, 1, 2 and 3.
Now,

\[P\left( X = 0 \right) = P\left(\text{ TTT }\right) = \frac{1}{8}, P\left( X = 1 \right) = P\left(\text{HTT or TTH or THT }\right) = \frac{3}{8}\]
\[P\left( X = 2 \right) = P\left(\text{ HTH or THH or HHT }\right) = \frac{3}{8}, P\left( X = 3 \right) = P\left( HHH \right) = \frac{1}{8}\]

Thus, the probability distribution of X is given by

x (X)
0
\[\frac{1}{8}\]
1
\[\frac{3}{8}\]
2
\[\frac{3}{8}\]
3
\[\frac{1}{8}\]

 

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Chapter 32: Mean and Variance of a Random Variable - Exercise 32.1 [Page 14]

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RD Sharma Mathematics [English] Class 12
Chapter 32 Mean and Variance of a Random Variable
Exercise 32.1 | Q 8 | Page 14

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