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Question
Find the area of an isosceles triangle whose perimeter is 50cm and the base is 24cm.
Solution
The sum of the equal sides of the given Isosceles triangle
= 50 - 24
= 26
So, each the equal sides of the given Isosceles triangle =
`(1)/(2)(26)`
= 13cm
We know that, Area of a Triangle whose sides are a, b, and c and semiperimeter is s is given by `sqrt("s"("s" - "a")("s" - "b")("s" - "c")); "s" = ("a" + "b" + "c")/(2)`
Here, sides are 13cm, 13cm and 24cm
s = `"P"/(2)`
= `(50)/(2)`
= 25
Area
= `sqrt(25(25 - 13)(25 - 13)(25 - 24)`
= `sqrt(25(12)(12)(1)`
= 5 x 12
= 60cm2.
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