Advertisements
Advertisements
Question
Find the area of the following triangle:
Solution
Area of triangle = `1/2 xx "Base" xx "Height"`
Base = 3 cm,
Height = 2 cm
Area = `1/2 xx 3 xx 2`
= 3cm2
APPEARS IN
RELATED QUESTIONS
Find the values of k for which the points A(k + 1, 2k), B(3k, 2k + 3) and (5k – 1, 5k) are collinear.
Prove that the area of a triangle with vertices (t, t −2), (t + 2, t + 2) and (t + 3, t) is independent of t.
The two opposite vertices of a square are (− 1, 2) and (3, 2). Find the coordinates of the other two vertices.
Show that points A (a, b + c), B (b, c + a), C (c, a + b) are collinear.
Find equation of line joining (3, 1) and (9, 3) using determinant.
Find the area of a triangle whose vertices are
(a, c + a), (a, c) and (−a, c − a)
Prove that the points (a, b), (a1, b1) and (a −a1, b −b1) are collinear if ab1 = a1b.
Show that the points A(-5,6), B(3,0) and C(9,8) are the vertices of an isosceles right-angled triangle. Calculate its area.
The area of a triangle with vertices (–3, 0), (3, 0) and (0, k) is 9 sq.units. The value of k will be ______.
Points A(3, 1), B(12, –2) and C(0, 2) cannot be the vertices of a triangle.
