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Tamil Nadu Board of Secondary EducationSSLC (English Medium) Class 9

Find the area of the unshaded region - Mathematics

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Question

Find the area of the unshaded region

Sum

Solution

Since ABD is a right angle triangle

AB2 = AD2 + BD2

= 122 + 162

= 144 + 256

= 400

AB = `sqrt(400)`

= 20 cm

Area of the right angle triangle = `1/2` bh sq.unit

= `1/2 xx 12 xx 16  "cm"^2`

= 6 × 16 cm2

= 96 cm2

To find the Area of the triangle ABC

Here a = 42 cm, b = 34 cm, c = 20 cm

s = `("a" + "b" + "c")/2`

= `(42 + 34 + 20)/2 "cm"`

= `96/2`

= 48 cm

s – a = 48 – 42 = 6 cm

s – b = 48 – 34 = 14 m

s – c = 48 – 20 = 28 m

Area of triangle

= `sqrt("s"("s" - "a")("s" - "b")("s" - "c"))`

= `sqrt(48 xx 6 xx 14 xx 28)`

= `sqrt(2^4 xx 3 xx 2 xx 3 xx 2 xx 7 xx 2^2 xx 7)`

= `sqrt(2^8 xx 3^2 xx 7^2)`

= 16 × 3 × 7 cm2

= 336 cm2

Area of the unshaded region = Area of the ΔABC – Area of the ΔABD

= (336 – 96) cm2

= 240 cm2

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Chapter 7: Mensuration - Exercise 7.1 [Page 252]

APPEARS IN

Samacheer Kalvi Mathematics [English] Class 9 TN Board
Chapter 7 Mensuration
Exercise 7.1 | Q 6 | Page 252

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