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Question
Find the distance of the origin from the line 7x + 24y – 50 = 0
Solution
Let p be the perpendicular distance of origin from the line 7x + 24y – 50 = 0
Here, a = 7, b = 24, c = – 50
∴ p = `|"c"/sqrt("a"^2 + "b"^2)|`
∴ p = `|(-50)/sqrt(7^2 + 24^2)|`
= `|(-50)/sqrt(49 + 576)|`
= `|(-50)/25|`
= 2 units
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