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Question
Find the equation of a line that cuts off equal intercepts on the coordinate axes and passes through the point (2, 3).
Solution
Line AB passes through the point P(2, 3) and makes equal intercepts on the coordinate axes.
OA = OB
∠BAO = 45°,
∠BAX = 135°
Slope of AB, m = tan 135° = –1
Equation of line, y – y1 = m(x – x1)
Where x1 = 2, Y1 = 3 and m = –1
y – 3 = – (x – 2)
or x + y – 5 = 0
or x + y = 5
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