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Three Vertices of a Parallelogram Taken in Order Are (−1, −6), (2, −5) and (7, 2). the Fourth Vertex is - Mathematics

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Question

Three vertices of a parallelogram taken in order are (−1, −6), (2, −5) and (7, 2). The fourth vertex is

Options

  •  (1, 4)

  • (4, 1)

  •  (1, 1)

  •  (4, 4)

  •  (0, 0)

MCQ

Solution

 (4,1)

Let A(−1, −6), B(2, −5) and C(7, 2) be the given vertex. Let D(h, k) be the fourth vertex.
The midpoints of AC and BD are \[\left( 3, - 2 \right) \text { and } \left( \frac{2 + h}{2}, \frac{- 5 + k}{2} \right)\]  respectively.

We know that the diagonals of a parallelogram bisect each other.

\[\therefore 3 = \frac{2 + h}{2} and - 2 = \frac{- 5 + k}{2}\]

\[ \Rightarrow h = 4 \text { and } k = 1\]

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Chapter 23: The straight lines - Exercise 23.21 [Page 134]

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RD Sharma Mathematics [English] Class 11
Chapter 23 The straight lines
Exercise 23.21 | Q 26 | Page 134

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