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Question
Find the equation of the circle with centre at (−3, −2) and radius 6.
Solution
The equation of a circle with centre at (h, k) and radius ‘r’ is given by
(x − h)2 + (y − k)2 = r2
Here, h = −3, k = −2 and r = 6
∴ The required equation of the circle is
[x − (−3)2] + [y − (−2)]2 = 62
∴ (x + 3)2 + (y + 2)2 = 36
∴ x2 + 6x + 9 + y2 + 4y + 4 − 36 = 0
∴ x2 + y2 + 6x + 4y − 23 = 0
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