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Question
Find the general solution of the following equation:
tan θ = `(1)/(sqrt(3))`
Solution
The general solution of tan θ = tan α is
θ = nπ + α, n ∈ Z
Now,
`tan θ = 1/(sqrt(3)) = tan π/6 ...[∵ tan π/6 = 1/(sqrt(3))]`
∴ the required general solution is
θ = nπ + `pi/(6)`, n ∈ Z.
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