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Question
Find the length of the shadow on the ground of a pole of height 18m when angle of elevation θ of the sun is such that tan θ = `6/7`.
Solution
Let the length of the shadow be ‘x’ m
Given, tan θ = `6/7`
= `"Perpendicular"/"Base"`
`\implies (AB)/(BC) = 6/7`
`\implies 18/x = 6/7`
`\implies` x = `(7 xx 18)/6`
= 7 × 3
= 21 m
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