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Question
Find the slope of the diagonals of a quadrilateral with vertices A(1, 7), B(6, 3), C(0, –3) and D(–3, 3).
Solution
Suppose ABCD is the given quadrilateral.
\[\therefore\text{Slope of line AC}=\frac{y_2-y_1}{x_2-x_1}\]
Slope of AC = \[\frac{7 + 3}{1 - 0} = \frac{10}{1} = 10\]
\[\therefore\text{Slope of line BD}=\frac{y_2-y_1}{x_2-x_1}\]
Slope of BD = \[\frac{3 - 3}{6 + 3} = 0\]
∴ The slopes of the diagonals of the quadrilateral are 10 and 0.
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