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Question
Find the squares of the following:
(2a + 3b - 4c)
Solution
Using (a + b + c)2
= a2 + b2 + c2 + 2ab + 2bc + 2ac
(2a +3b - 4c)2
= (2a)2 + (3b)2 + (4c)2 + 2(2a)(3b) + 2(3b)(-4c) + 2(2a)(-4c)
= 4a2 + 9b2 + 16c2 + 12ab - 24bc - 8ac.
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