Advertisements
Advertisements
Question
Find the vector and Cartesian equations of the plane passing through the points (2, 2 –1), (3, 4, 2) and (7, 0, 6). Also find the vector equation of a plane passing through (4, 3, 1) and parallel to the plane obtained above.
Solution
step 1
The given points are A(2, 2, –1), B(3, 4, 2) and C(7, 0, 6)
Let `vec"a" = 2hat"i" + 2hat"j" - hat"k"`
`vec"b" = 3hat"i" + 4hat"j" + 2hat"k"`
`vec"c" = 7hat"i" + 6hat"k"`
Hence the vector equation of the plane passing through the points
`(vec"r"- vec"a").(vec"AB" xx vec"AC") = 0`
= `(vec"r" - vec"a").((vec"b" - vec"a") xx (vec"c" - vec"a")) = 0`
Now
`vec"b"- vec"a" = (3hat"i"+4hat"j" + 2hat"k")-(2hat"i"+ 2hat"j"-hat"k")`
⇒ `hat"i" + 2hat"j" + 3hat"k"`
`vec"c" - vec"a" = (7hat"i" + 6hat"k") - (2hat"i" + 2hat"j" - hat"k")`
= `5hat"i" - 2hat"j" + 7hat"k"`
So the required vector equation of plane is
`[vec"r" - (2hat"i" + 2hat"j" - hat"k")].[(hat"i" + 2hat"j" + 3hat"k") xx (5hat"i" - 2hat"j" + 7hat"k")] = 0`
Step 2
`(vec"b" - vec"a") xx (vec"c" - vec"a") = |(hat"i",hat"j",hat"k"),(1,2,3),(5,-2,7)|`
= `hat"i" (14 +6) -hat"j" (7 -15) + hat"k" (-2-10)`
= `20hat"i" + 8hat"j" - 12hat"k"`
⇒ `(vec"r" - (2hat"i" + 2hat"j" - hat"k")) . (20hat"i" + 8hat"j"-12hat"k") = 0`
`(vec"r" - (2hat"i" + 2hat"j" - hat"k")) . (5hat"i" + 2hat"j"- 3hat"k") = 0`
`vecr . (5hat"i" + 2hat"j"- 3hat"k") = (2hat"i" + 2hat"j" - hat"k"). (5hat"i" + 2hat"j", 3hat"k")`
`vecr . (5hat"i" + 2hat"j"- 3hat"k") = 10 + 4 + 3`
`vecr . (5hat"i" + 2hat"j"-3hat"k") = 17`
This is the required vector equation of the plane
Step 3
The Cartesian Equation of the plane passing through the three points is given as below-
5x + 2y − 3z − 17 = 0
This is the required cartesian equation of the plane.
The equation of plane parallel to 5x + 2y − 3z − 17 = 0 will be 5x + 2y − 3z + λ = 0
∴ it passes through (4, 3, 1).
So, 5 × 4 + 2 × 3 − 3 × 1 + λ = 0
20 + 6 − 3 + λ = 0
So, λ = −23
so the equation of the plane will be
5x + 2y − 3z − 23 = 0
5x + 2y − 3z = 23
so the vector form of the equation of plane will be
`vecr. (5hat"i" + 2hat"j" - 3hat"k") = 23`
RELATED QUESTIONS
Parametric form of the equation of the plane is `bar r=(2hati+hatk)+lambdahati+mu(hat i+2hatj+hatk)` λ and μ are parameters. Find normal to the plane and hence equation of the plane in normal form. Write its Cartesian form.
Write the vector equation of the plane, passing through the point (a, b, c) and parallel to the plane `vec r.(hati+hatj+hatk)=2`
Find the vector equation of the plane which contains the line of intersection of the planes `vecr (hati+2hatj+3hatk)-4=0` and `vec r (2hati+hatj-hatk)+5=0` which is perpendicular to the plane.`vecr(5hati+3hatj-6hatk)+8=0`
Find the vector equation of the plane with intercepts 3, –4 and 2 on x, y and z-axis respectively.
Find the equation of the plane which contains the line of intersection of the planes
`vecr.(hati-2hatj+3hatk)-4=0" and"`
`vecr.(-2hati+hatj+hatk)+5=0`
and whose intercept on x-axis is equal to that of on y-axis.
Find the Cartesian equation of the following planes:
`vecr.(hati + hatj-hatk) = 2`
Find the Cartesian equation of the following planes:
`vecr.(2hati + 3hatj-4hatk) = 1`
In the following cases, find the coordinates of the foot of the perpendicular drawn from the origin.
2x + 3y + 4z – 12 = 0
In the following cases, find the coordinates of the foot of the perpendicular drawn from the origin.
3y + 4z – 6 = 0
In the following cases, find the coordinates of the foot of the perpendicular drawn from the origin.
x + y + z = 1
In the following cases, find the coordinates of the foot of the perpendicular drawn from the origin.
5y + 8 = 0
Find the vector and Cartesian equation of the planes that passes through the point (1, 4, 6) and the normal vector to the plane is `hati -2hatj + hatk`
The Cartesian equation of the line is 2x - 3 = 3y + 1 = 5 - 6z. Find the vector equation of a line passing through (7, –5, 0) and parallel to the given line.
Find the image of a point having the position vector: `3hati - 2hatj + hat k` in the plane `vec r.(3hati - hat j + 4hatk) = 2`
Find the vector equation of the line passing through (1, 2, 3) and parallel to the planes \[\vec{r} \cdot \left( \hat{i} - \hat{j} + 2 \hat{k} \right) = 5 \text{ and } \vec{r} \cdot \left( 3 \hat{i} + \hat{j} + \hat{k} \right) = 6 .\]
Find the vector and cartesian equations of the plane passing throuh the points (2,5,- 3), (-2, - 3,5) and (5,3,-3). Also, find the point of intersection of this plane with the line passing through points (3, 1, 5) and (–1, –3, –1).
Find the equation of the plane passing through the intersection of the planes `vec(r) .(hat(i) + hat(j) + hat(k)) = 1"and" vec(r) . (2 hat(i) + 3hat(j) - hat(k)) +4 = 0 `and parallel to x-axis. Hence, find the distance of the plane from x-axis.
Find the Cartesian equation of the plane, passing through the line of intersection of the planes `vecr. (2hati + 3hatj - 4hatk) + 5 = 0`and `vecr. (hati - 5hatj + 7hatk) + 2 = 0` intersecting the y-axis at (0, 3).
Find the vector and cartesian equation of the plane passing through the point (2, 5, - 3), (-2, -3, 5) and (5, 3, -3). Also, find the point of intersection of this plane with the line passing through points (3, 1, 5) and (-1, -3, -1).
Find the vector equation of the plane that contains the lines `vecr = (hat"i" + hat"j") + λ (hat"i" + 2hat"j" - hat"k")` and the point (–1, 3, –4). Also, find the length of the perpendicular drawn from the point (2, 1, 4) to the plane thus obtained.
The Cartesian equation of the plane `vec"r" * (hat"i" + hat"j" - hat"k")` = 2 is ______.
The vector equation of the line `(x - 5)/3 = (y + 4)/7 = (z - 6)/2` is `vec"r" = 5hat"i" - 4hat"j" + 6hat"k" + lambda(3hat"i" + 7hat"j" + 2hat"k")`.
Find the vector and the cartesian equations of the plane containing the point `hati + 2hatj - hatk` and parallel to the lines `vecr = (hati + 2hatj + 2hatk) + s(2hati - 3hatj + 2hatk)` and `vecr = (3hati + hatj - 2hatk) + t(hati - 3hatj + hatk)`