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Question
Find the vector and Cartesian equation of the planes that passes through the point (1, 4, 6) and the normal vector to the plane is `hati -2hatj + hatk`
Solution
The position vector of the point (1, 4, 6) is veca = `hati + 4hatj + 6hatk`
The normal vector `vecN`perpendicular to the plane is `vecN = hati - 2hatj + hatk`
The vector equation of the plane is given by, `(vecr - veca).vecN = 0`
This is the Cartesian equation of the required plane.
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