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Question
Find the Cartesian equation of the following planes:
`vecr.[(s-2t)hati + (3 - t)hatj + (2s + t)hatk] = 15`
Solution
`vecr.[(s-2t)hati + (3 - t)hatj + (2s + t)hatk] = 15` ....(1)
For any arbitrary point P (x, y, z) on the plane, position vector `vecr` is given by,
`vecr = xhati + yhatj - zhatk`
Substituting the value of `hatr` in equation (1), we obtain
This is the Cartesian equation of the given plane.
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