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NCERT solutions for Mathematics [English] Class 12 chapter 11 - Three Dimensional Geometry [Latest edition]

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NCERT solutions for Mathematics [English] Class 12 chapter 11 - Three Dimensional Geometry - Shaalaa.com
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Solutions for Chapter 11: Three Dimensional Geometry

Below listed, you can find solutions for Chapter 11 of CBSE, Karnataka Board PUC NCERT for Mathematics [English] Class 12.


EXERCISE 11.1EXERCISE 11.2Miscellaneous Exercise
EXERCISE 11.1 [Page 381]

NCERT solutions for Mathematics [English] Class 12 11 Three Dimensional Geometry EXERCISE 11.1 [Page 381]

EXERCISE 11.1 | Q 1. | Page 381

If a line makes angles 90°, 135°, 45° with the x, y and z axes respectively, find its direction cosines.

EXERCISE 11.1 | Q 2. | Page 381

Find the direction cosines of a line which makes equal angles with the coordinate axes.

EXERCISE 11.1 | Q 3. | Page 381

If a line has the direction ratios −18, 12, −4, then what are its direction cosines?

EXERCISE 11.1 | Q 4. | Page 381

Show that the points (2, 3, 4), (−1, −2, 1), (5, 8, 7) are collinear.

EXERCISE 11.1 | Q 5. | Page 381

Find the Direction Cosines of the Sides of the triangle Whose Vertices Are (3, 5, -4), (-1, 1, 2) and (-5, -5, -2).

EXERCISE 11.2 [Pages 389 - 390]

NCERT solutions for Mathematics [English] Class 12 11 Three Dimensional Geometry EXERCISE 11.2 [Pages 389 - 390]

EXERCISE 11.2 | Q 1. | Page 389

Show that the three lines with direction cosines `12/13, (-3)/13, (-4)/13;  4/13, 12/13, 3/13;  3/13, (-4)/13, 12/13 ` are mutually perpendicular.

EXERCISE 11.2 | Q 2. | Page 389

Show that the line through the points (1, −1, 2) (3, 4, −2) is perpendicular to the line through the points (0, 3, 2) and (3, 5, 6).

EXERCISE 11.2 | Q 3. | Page 389

Show that the line through the points (4, 7, 8) (2, 3, 4) is parallel to the line through the points (−1, −2, 1), (1, 2, 5).

EXERCISE 11.2 | Q 4. | Page 389

Find the equation of the line which passes through the point (1, 2, 3) and is parallel to the vector `3hati+2hatj-2hatk`.

EXERCISE 11.2 | Q 5. | Page 389

Find the equation of the line in vector and in Cartesian form that passes through the point with position vector `2hati -hatj+4hatk`  and is in the direction `hati + 2hatj - hatk`.

EXERCISE 11.2 | Q 6. | Page 389

Find the Cartesian equation of the line which passes through the point (−2, 4, −5) and parallel to the line given by `(x+3)/3 = (y-4)/5 = (z+8)/6`.

EXERCISE 11.2 | Q 7. | Page 389

The Cartesian equation of a line is `(x-5)/3 = (y+4)/7 = (z-6)/2` Write its vector form.

EXERCISE 11.2 | Q 8. (i) | Page 389

Find the angle between the following pair of lines:

`vecr = 2hati - 5hatj + hatk + lambda(3hati - 2hatj + 6hatk) and vecr = 7hati - 6hatk + mu(hati + 2hatj + 2hatk)`

EXERCISE 11.2 | Q 8. (ii) | Page 390

Find the angle between the following pair of lines:

`vecr = 3hati + hatj - 2hatk + lambda(hati - hatj - 2hatk) and vecr = 2hati - hatj -56hatk + mu(3hati - 5hatj - 4hatk)`

EXERCISE 11.2 | Q 9. (i) | Page 390

Find the angle between the following pairs of lines: 

`(x-2)/2 = (y-1)/5 = (z+3)/(-3)` and `(x+2)/(-1) = (y-4)/8 = (z -5)/4`

EXERCISE 11.2 | Q 9. (ii) | Page 390

Find the angle between the following pairs of lines:

`x/y = y/2 = z/1` and `(x-5)/4 = (y-2)/1 = (z - 3)/8`

EXERCISE 11.2 | Q 10. | Page 390

Find the values of p so the line `(1-x)/3 = (7y-14)/2p = (z-3)/2` and `(7-7x)/(3p) = (y -5)/1 = (6-z)/5` are at right angles.

EXERCISE 11.2 | Q 11. | Page 390

Show that the lines `(x-5)/7 = (y + 2)/(-5) = z/1` and `x/1 = y/2 = z/3` are perpendicular to each other.

EXERCISE 11.2 | Q 12. | Page 390

Find the shortest distance between the lines: 

`vecr = (hati+2hatj+hatk) + lambda(hati-hatj+hatk)` and `vecr = 2hati - hatj - hatk + mu(2hati + hatj + 2hatk)`

EXERCISE 11.2 | Q 13. | Page 390

Find the shortest distance between the lines.

`(x + 1)/7 = (y + 1)/(- 6) = (z + 1)/1` and `(x - 3)/1 = (y - 5)/(- 2) = (z - 7)/1`.

EXERCISE 11.2 | Q 14. | Page 390

Find the shortest distance between the lines whose vector equations are `vecr = (hati + 2hatj + 3hatk) + lambda(hati - 3hatj + 2hatk)` and `vecr = 4hati + 5hatj + 6hatk + mu(2hati + 3hatj + hatk)`.

EXERCISE 11.2 | Q 15. | Page 390

Find the shortest distance between the lines whose vector equations are `vecr = (1-t)hati + (t - 2)hatj + (3 -2t)hatk` and `vecr = (s+1)hati + (2s + 1)hatk`.

Miscellaneous Exercise [Pages 390 - 391]

NCERT solutions for Mathematics [English] Class 12 11 Three Dimensional Geometry Miscellaneous Exercise [Pages 390 - 391]

Miscellaneous Exercise | Q 1. | Page 390

Find the angle between the lines whose direction ratios are a, b, c and b − c, c − a, a − b.

Miscellaneous Exercise | Q 2. | Page 390

Find the equation of a line parallel to x-axis and passing through the origin.

Miscellaneous Exercise | Q 3. | Page 391

If the lines `(x-1)/(-3) = (y -2)/(2k) = (z-3)/2 and (x-1)/(3k) = (y-1)/1 = (z -6)/(-5)` are perpendicular, find the value of k.

Miscellaneous Exercise | Q 4. | Page 391

Find the shortest distance between lines `vecr = 6hati + 2hatj + 2hatk + lambda(hati - 2hatj + 2hatk)` and `vecr =-4hati - hatk + mu(3hati - 2hatj - 2hatk)`.

Miscellaneous Exercise | Q 5. | Page 391

Find the vector equation of the line passing through the point (1, 2, − 4) and perpendicular to the two lines: 

`(x -8)/3 = (y+19)/(-16) = (z - 10)/7 and (x - 15)/3 = (y - 29)/8 = (z- 5)/(-5)`

Solutions for 11: Three Dimensional Geometry

EXERCISE 11.1EXERCISE 11.2Miscellaneous Exercise
NCERT solutions for Mathematics [English] Class 12 chapter 11 - Three Dimensional Geometry - Shaalaa.com

NCERT solutions for Mathematics [English] Class 12 chapter 11 - Three Dimensional Geometry

Shaalaa.com has the CBSE, Karnataka Board PUC Mathematics Mathematics [English] Class 12 CBSE, Karnataka Board PUC solutions in a manner that help students grasp basic concepts better and faster. The detailed, step-by-step solutions will help you understand the concepts better and clarify any confusion. NCERT solutions for Mathematics Mathematics [English] Class 12 CBSE, Karnataka Board PUC 11 (Three Dimensional Geometry) include all questions with answers and detailed explanations. This will clear students' doubts about questions and improve their application skills while preparing for board exams.

Further, we at Shaalaa.com provide such solutions so students can prepare for written exams. NCERT textbook solutions can be a core help for self-study and provide excellent self-help guidance for students.

Concepts covered in Mathematics [English] Class 12 chapter 11 Three Dimensional Geometry are Introduction of Three Dimensional Geometry, Angle Between Two Lines, Equation of a Plane in Normal Form, Equation of a Plane Perpendicular to a Given Vector and Passing Through a Given Point, Shortest Distance Between Two Lines, Equation of a Line in Space, Direction Cosines and Direction Ratios of a Line, Three - Dimensional Geometry Examples and Solutions, Equation of a Plane Passing Through Three Non Collinear Points, Relation Between Direction Ratio and Direction Cosines, Intercept Form of the Equation of a Plane, Coplanarity of Two Lines, Distance of a Point from a Plane, Angle Between Line and a Plane, Angle Between Two Planes, Vector and Cartesian Equation of a Plane, Distance of a Point from a Plane, Plane Passing Through the Intersection of Two Given Planes, Introduction of Three Dimensional Geometry, Angle Between Two Lines, Equation of a Plane in Normal Form, Equation of a Plane Perpendicular to a Given Vector and Passing Through a Given Point, Shortest Distance Between Two Lines, Equation of a Line in Space, Direction Cosines and Direction Ratios of a Line, Three - Dimensional Geometry Examples and Solutions, Equation of a Plane Passing Through Three Non Collinear Points, Relation Between Direction Ratio and Direction Cosines, Intercept Form of the Equation of a Plane, Coplanarity of Two Lines, Distance of a Point from a Plane, Angle Between Line and a Plane, Angle Between Two Planes, Vector and Cartesian Equation of a Plane, Distance of a Point from a Plane, Plane Passing Through the Intersection of Two Given Planes.

Using NCERT Mathematics [English] Class 12 solutions Three Dimensional Geometry exercise by students is an easy way to prepare for the exams, as they involve solutions arranged chapter-wise and also page-wise. The questions involved in NCERT Solutions are essential questions that can be asked in the final exam. Maximum CBSE, Karnataka Board PUC Mathematics [English] Class 12 students prefer NCERT Textbook Solutions to score more in exams.

Get the free view of Chapter 11, Three Dimensional Geometry Mathematics [English] Class 12 additional questions for Mathematics Mathematics [English] Class 12 CBSE, Karnataka Board PUC, and you can use Shaalaa.com to keep it handy for your exam preparation.

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