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Question
Find x and y if `[(2x, x),(y, 3y)][(3),(2)] = [(16),(9)]`
Solution
`[(2x, x),(y, 3y)][(3),(2)] = [(16),(9)]`
⇒ `[(2x xx 3 + x xx 2),(y xx 3 + 3y xx 2)] = [(16),(9)]`
⇒ `[(6x + 2x),(3y + 6y)] = [(16),(9)]`
⇒ `[(8x),(9y)] = [(16),(9)]`
Comparing, we get
8x = 16
⇒ x = `(16)/(8)` = 2
and
9y = 9
⇒ y = `(9)/(9)` = 1
Here x = 2, y = 1.
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