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Question
A = `[(1, 0),(2, 1)] and "B" = [(2, 3),(-1, 0)]` Find A2 + AB + B2
Solution
Given that
A = `[(1, 0),(2, 1)]`
B = `[(2, 3),(-1, 0)]`
A2 = A x A = `[(1, 0),(2, 1)] xx [(1, 0),(2, 1)]`
= `[(1 xx 1 + 0 xx 2, 1 xx 0 + 0 xx 1),(2 xx 1 + 1 xx 2, 2 xx 0 + 1 xx 1)]`
= `[(1 + 0, 0 + 0),(2+ 2, 0+ 1)]`
= `[(1, 0),(4, 1)]`
A x B = `[(1, 0),(2, 1)] xx [(2, 3),(-1, 0)]`
= `[(1 xx 2 + 0 xx -1 , 1 xx 3 + 0 xx 0),(2 xx 2 + 1 xx 1, 2 xx 3 + 1 xx 0)]`
= `[(2, 3),(3, 6)]`
B2 = B x B = `[(2, 3),(-1, 0)] xx [(2, 3),(-1, 0)]`
= `[(2 xx 2 + 3 xx (-1), 2 xx 3 + 3 xx 0),(-1 xx 2 + 0 xx (-1), -1 xx 3 + 0 xx 0)]`
= `[(4 - 3, 6 + 0),(-2 + 0, -3 + 0)]`
= `[(1, 6),(-2, -3)]`
A2 + AB + B2 = `[(1, 0),(4, 1)] + [(2, 3),(3, 6)] + [(1, 6),(-2, -3)]`
= `[(1 + 2 + 1, 0 + 3 + 6),(4 + 3 - 2, 1 + 6 + -3)]`
= `[(4, 9),(5, 4)]`.
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