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For the following probability density function of a random variable X, find P(|X| < 1). ;for,otherwisef(x)=x+218; for-2<x<4 =0, otherwise - Mathematics and Statistics

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Question

For the following probability density function of a random variable X, find P(|X| < 1).

`{:(f(x) = (x + 2)/18,";"  "for" -2 < x < 4),(               = 0,","  "otherwise"):}`

Sum

Solution

P(|X| < 1) = P(–1 < x < 1)

= `int_-1^1 (x + 2)/18 dx`

= `1/18 [x^2/2 + 2x]_-1^1`

= `1/18 {(1/2 + 2) - (1/2 - 2)}`

= `1/18 {5/2 + 3/2}`

= `1/18 xx 4`

= `2/9`

P(|X| < 1) = `2/9`

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Probability Distribution of a Continuous Random Variable
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