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Question
If `A =[[2,-3],[3,5]]` then find A-1 by adjoint method.
Solution
Given `A =[[2,-3],[3,5]]`
`therefore |A| =|[2,-3],[3,5]|=10+9=19ne0`
∴A-1 exist
A11 = (-1)1+1.M11 = 5
A12 = (-1)1+2.M12 = -3
A21 = (-1)2+1.M21 = -(-3) = 3
A22 = (-1)2+2.M22 = 2
Hence, matrix of the co-factors is
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