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Question
If `"a" + 1/"a" = 6;`find `"a"^2 - 1/"a"^2`
Sum
Solution
`"a"^2 - 1/"a"^2`
= `("a" + 1/"a")("a" - 1/"a")`
= (6)`(±4sqrt(2))`
= ±24`sqrt(2)`.
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