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Question
if `A = [(3,x),(0,1)], B = [(9,16),(0,-y)]`, Find x and y where `A^2 = B`
Solution
Given `A = [(3,x),(0,1)], B = [(9,16),(0,-y)]` and `A^2 = B`
Now `A^2 = A xx A = [(3, x),(0,1) ]xx [(3,x),(0,1)] = [(9, 3x + x),(0,1)] = [(9,4x),(0,1)]`
We have `A^2 = B`
Two matrices are equal if each and every corresponding element is equal.
Thus `[(9,4x),(0,1)] = [(9,16),(0,-y)]`
`=> 4x = 16 and 1 = -y`
`=> x = 4 and y = -1`
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