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Question
If a current of 0.5 ampere flows through a metallic wire for 2 hours, then how many electrons would flow through the wire?
Solution
I = 0.5 A
t = 2 hours = 2 × 60 × 60 s = 7200 s
Thus, Q = It
= 0.5 A × 7200 s
= 3600 C
We know that 96487C = 6.023 × 1023 number of electrons
Then
`3600 "C" = (6.023 xx 10^(23) xx 3600)/9648` number of electrons
= 2.25 × 1022 number of electrons
Hence, 2.25 × 1022 number of electrons will flow through the wire.
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