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Question
If a wire is bent into the shape of a square, then the area of the square is 81 cm2. When wire is bent into a semi-circular shape, then the area of the semi-circle will be ______.
Options
22 cm2
44 cm2
77 cm2
154 cm2
Solution
If a wire is bent into the shape of a square, then the area of the square is 81 cm2. When wire is bent into a semi-circular shape, then the area of the semi-circle will be 77 cm2.
Explanation:
We have given that a wire is bent in the form of square of side a cm such that the area of the square is `81 cm^2`. If we bent the same wire in the form of a semicircle with radius r cm, the perimeter of the wire will not change.
∴ perimeter of the square = perimeter of semi circle
`4a=1/2 (2pir)+2r` ...(1)
We know that area of the square = 81 cm2
∴ a2 = 81
∴ a = 9
Now we will substitute the value of a in the equation (1),
`4xx9=1/2(2pi r)+2r`
`∴ 36=1/2(2pir)+2r`
`∴36=(pir)+2r`
`∴36=r(pi+2)`
Now we will substitute `pi=22/7`
`∴36=r(22/7+2)`
`∴36=r((22+14)/7)`
`∴36=r(36/7)`
Multiplying both sides of the equation by 7 we get, 36 × 7 = r × 36
Now we will divide both sides of the equation by 36 we get, r = 7
Therefore, radius of the semi circle is 7cm.
Now we will find the area of the semicircle.
Area of the semicircle = `1/2xxpir^2`
= `1/2xxpixx7^2`
= `1/2xx22/7xx7^2`
= 11 × 7
= 77
Therefore, the area of the semicircle is 77 cm2.
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