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Question
If below fig, if AB || CD and CD || EF, find ∠ACE.
Solution
Since EF || CD
∴ EFC + `∠`ECD = 180° [co-interior angles are supplementary]
⇒ `∠`ECD =180° -130° = 50°
Also BA || CD
⇒`∠`BAC = `∠`ACD = 70° [alternative angles]
But
`∠`ACE + `∠`ECD = 70°
⇒ `∠`ACE = 70° - 50° = 20°
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