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Question
In below fig, OP, OQ, OR and OS arc four rays. Prove that:
∠POQ + ∠QOR + ∠SOR + ∠POS = 360°
Solution
Given that
OP, OQ, OR and OS are four rays
You need to produce any of the ray OP, OQ, OR and OS backwards to a point in the figure. Let us produce ray OQ backwards to a point
T so that TOQ is a line
Ray OP stands on the TOQ
Since `∠`TOP, `∠`POQ is linear pair
`∠`TOP + `∠`POQ = 180° .......(1)
Similarly, ray OS stands on the line TOQ
∴`∠`TOS + `∠`SOQ = 180° ..........(2)
But `∠`SOQ = `∠`SOR + `∠`QOR
So, (2), becomes
`∠`TOS + `∠`SOR + `∠`OQR = 180°
Now, adding (1) and (3) you get
`∠`TOP + `∠`POQ + `∠`TOS + `∠`SOR + `∠`QOR = 360°
⇒ `∠`TOP + `∠`TOS = `∠`POS
∴ (4) becomes
`∠`POQ + `∠`QOR + `∠`SOR + `∠`POS = 360°
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