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Question
What value of y would make AOB a line in below fig, if ∠AOC = 4y and ∠BOC = (6y +
30)
Solution
Since `∠`AOC, `∠`BOC are linear pair
⇒ `∠`AOC + `∠`BOC = 180°
⇒ 6 y + 30 + 4 y = 180°
⇒ 10 y + 30 = 180°
⇒ 10 y = 180° - 30°
⇒ 10 y = 150°
⇒ y = `(150°)/10`
⇒ y = 15°
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