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Question
If figure OPRQ is a square and ∠MLN = 90°. Prove that ∆LOP ~ ∆QMO
Solution
In ∆LOP and ∆QMO
∠OLP = ∠OQM = 90°
∠LOP = ∠OMQ ...(Since OQRP is a square OP || MN)
∴ ∆LOP~ ∆QMO ...(By AA similarity)
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